因式分解-ax^2+4ax+5a
问题描述:
因式分解-ax^2+4ax+5a
答
-ax^2+4ax+5a
=-a(x^2-4x-5)
=-a(x-5)(x+1)
因式分解-ax^2+4ax+5a
-ax^2+4ax+5a
=-a(x^2-4x-5)
=-a(x-5)(x+1)