(a+1)x^2+(a+1)x-6a-6

问题描述:

(a+1)x^2+(a+1)x-6a-6

很简单的,按照下面的步骤做:
(a+1)x2+(a+1)x-6a-6
=(a+1)x2+(a+1)x-6(a+1)
=(a+1)( x2+x-6)
=(a+1)(x-3)(x+2)
其中用了提公因式法和十字相乘法,应该能明白吧!

(a+1)x^2+(a+1)x-6a-6
=(a+1)x^2+(a+1)x-6(a+1)
=(a+1)(x^2+x-6)
=(a+1)(x+3)(x-2)