cos100°cos40°+sin80°sin40°
问题描述:
cos100°cos40°+sin80°sin40°
答
cos100=-cos80
所以 原式=-(cos80cos10-sin40sin80)=-cos(80+40)=1/2
答
cos100°cos40°+sin80°sin40°=cos100°cos40°+sin100°sin40°=cos(100°-40°)=cos60°=1/2
答
cos100°=-cos80° cos(a+b)=cosacosb-sinasinb
所以原式=sin80°sin40°-cos80°cos40°=-COS120°=1/2
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