因式分解：1.y^2-y-12=0 2.y(y+5)=24 3 .(x+1)^2=√2(x+1) 4 .36x^2=9(x+1)^2 5 .(x-3)^2-3(3-x)-4=0
问题描述：
因式分解：1.y^2-y-12=0 2.y(y+5)=24 3 .(x+1)^2=√2(x+1) 4 .36x^2=9(x+1)^2 5 .(x-3)^2-3(3-x)-4=0
答
1.y^2-y-12=0 (y-4)(y+3)=0y=4 y=-32.y(y+5)=24y^2+5y-24=0(y-3)(y+8)=0y=3 y=-83 .(x+1)^2=√2(x+1)(x+1)^2-√2(x+1)=0(x+1)(x+1-√2)=0x=-1 x=√2-14 .36x^2=9(x+1)^236x^2-9(x+1)^2=0(6x+3(x+1))(6x-3(x+1))=0(9x...