5(x-1)/6-1≥2(x+1)/3 解不等式,

问题描述:

5(x-1)/6-1≥2(x+1)/3 解不等式,

5(x-1)/6-1≥2(x+1)/3
x-1≥2(x+1)/3
3x-3≥2(x+1)
3x-3≥2x+2
3x-2x≥5
x≥5

5(x-1)/6-1≥2(x+1)/3
两边同乘以6:
5(x-1) - 6 ≥ 4(x+1)
5x-5 - 6 ≥ 4x+4
移项:
5x-4x ≥ 4+5+6
x ≥ 15

5(x-1)/6-1≥2(x+1)/3
5*(x-1)-6≥2*2*(x+1) 【这步是左右两边同时乘以6】
5x-5-6≥4x+4
5x-4x≥5+6+4
x≥15