运筹学……对偶问题.maxz=x1+2x2+3x3+4x4-x1+x2-x3-3x4=56x1-7x2+3x3-5x4
问题描述:
运筹学……对偶问题.
maxz=x1+2x2+3x3+4x4
-x1+x2-x3-3x4=5
6x1-7x2+3x3-5x4
答
min z = 5y1+8y2+20y3
s.t.
-1y1+6y2+12y3 >=1
y1-7y2-9y3 >=2
-1y1+3y2-9y3 =0