填上合适的运算符号加减乘除()等,将其填进数字行列中,使五个版式的结果都等于1(数字顺序不变).5 4 3 2 =16 5 4 3 2 =17 6 5 4 3 2 =18 7 6 5 4 3 2 =19 8 7 6 5 4 3 2 =1
问题描述:
填上合适的运算符号加减乘除()等,将其填进数字行列中,使五个版式的结果都等于1(数字顺序不变).
5 4 3 2 =1
6 5 4 3 2 =1
7 6 5 4 3 2 =1
8 7 6 5 4 3 2 =1
9 8 7 6 5 4 3 2 =1
答
1 (5-4)*(3-2)=1
2 (6-5+4)/(3+2)=1
3 (7-6)*(5-4)*(3-2)=1
4 8+7-6-5-4+3-2=1
5 (9-8)*(7-6)*(5-4)*(3-2)=1
答
(5-4)×(3-2)=1
(6-5+4-3)/2=1
(7-6)/(5-4)/(3-2)=1
8+7-6-5-4+3-2=1
(9-8)/(7-6)/(5-4)/(3-2)=1
答
5+4÷3-2=1
(6-5+4-3)÷2=1
(7-6)÷(5-4)÷(3-2)=1
8+7-6-5-4+3-2=1
(9-8)÷(7-6)÷(5-4)÷(3-2)=1
答
(5-4)*(3-2)
((6-5)+(4-3))/2
(7-6)*(5-4)*(3-2)
(8-7)*((6-5)+(4-3))/2
(9-8)*(7-6)*(5-4)*(3-2)