【分解因式,需要过程】a²x²+16ax+64a²x²+16ax+64a^4-8a²b²+16b^4(a+y)²-14(a+y)+49x²y-2xy²+y³9x²-(2y+z)²
问题描述:
【分解因式,需要过程】a²x²+16ax+64
a²x²+16ax+64
a^4-8a²b²+16b^4
(a+y)²-14(a+y)+49
x²y-2xy²+y³
9x²-(2y+z)²
答
a²x²+16ax+64
=(ax)²+2*8*ax+8²
=(ax+8)²
a^4-8a²b²+16b^4
=(a²)²+2*a²*4b²+(4b²)²
=(a²-4b²)²
=(a+2b)²(a-2b)²
(a+y)²-14(a+y)+49
=(a+y+7)²
x²y-2xy²+y³
=y(x²-2xy+y²)
=y(x-y)²
9x²-(2y+z)²
=(3x+2y+z)(3x-2y-z)
答
a²x²+16ax+64=(ax+8)²
a^4-8a²b²+16b^4=(a²-4b²)²=(a+2b)²(a-2b)²
(a+y)²-14(a+y)+49=[(a+y)-7]²=(a+y-7)²
x²y-2xy²+y³=y(x²-2xy+y²)=y(x-y)²
9x²-(2y+z)²=[3x+(2y+z)][3x-(2y+z)]=(3x+2y+z)(3x-2y-z)