已知│x-y+1│与x2+8x+16互为相反数,求x2+2xy+y2的值．
问题描述：
已知│x-y+1│与x2+8x+16互为相反数,求x2+2xy+y2的值．
答
已知│x-y+1│与x2+8x+16互为相反数,求x2+2xy+y2的值．x-y+1=0;(1)(x+4)=0;x=-4;y=-4+1=-3;∴x2+2xy+y2=(x+y)²=(-4-3)²=49;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,...