(3/x)-6/(1-x)-(x+5)/(x^2-x)拜托各位了 3Q
问题描述：
(3/x)-6/(1-x)-(x+5)/(x^2-x)拜托各位了 3Q
计算的,初一下半学期的,写的清楚些
答
(3/x)-6/(1-x)-(x+5)/(x^2-x) =(3/x)+6/(x-1)-(x+5)/(x^2-x) =3(x-1)/(x^2-x)+6x/(x^2-x)-(x+5)/(x^2-x) =[3(x-1)+6x-(x+5)]/(x^2-x) =(3x-3+6x-x-5)/(x^2-x) =(8x-8)/(x^2-x) =8(x-1)/[x(x-1)] =8/x