已知x>0,y＞0,集合A={x^2+2,-x,-x-1},集合B={-y,-y/2,y+1)若A=B则x^2+y^2的值为
问题描述：
已知x>0,y＞0,集合A={x^2+2,-x,-x-1},集合B={-y,-y/2,y+1)若A=B则x^2+y^2的值为
1.若A=B则x^2+y^2的值为
2.A∩B=｛6｝,求A∪B
答
1、∵x>0,y＞0∴x^2+2>-x>-x-1y+1>-y/2>-y又∵A=B∴-x-1=-y-x=-y/2x²+2=y+1解得x=1,y=2x²+y²=1²+2²=52、∵x>0,y＞0.A∩B=｛6｝∴x²+2=6,y+1=6即x=2,y=5-x=-2,-x-1=-3-y=-5,-y/2=-2.5...