f【x】=e∧2x+(1-2t)e∧x+t²,求证当x≥0时,f【x】+cosx≥x+2当x≥0时,f【x】+cosx≥x+2
问题描述:
f【x】=e∧2x+(1-2t)e∧x+t²,求证当x≥0时,f【x】+cosx≥x+2当x≥0时,f【x】+cosx≥x+2
答
f【x】=e∧2x+(1-2t)e∧x+t²,求证当x≥0时,f【x】+cosx≥x+2当x≥0时,f【x】+cosx≥x+2