已知: 则:1+2+3+…+99+100+99+98+…+3+2+1=_.
问题描述:
已知:
则:1+2+3+…+99+100+99+98+…+3+2+1=______.
答
方法一:
1+2+3+…+99+100+99+98+…+3+2+1,
=1002,
=10000;
方法二:
(1+100)×100÷2×2-100,
=101×100-100,
=10100-100,
=10000;
故答案为:10000.