(a-c)²=b²-ac则∠B=

问题描述:

(a-c)²=b²-ac则∠B=

(a-c)²=b²-ac
a^2+c^2-2ac=b^2-ac
a^2+c^2-b^2=ac
cos∠B=(a^2+c^2-b^2)/(2ac)=1/2
∠B=60°