{t-1,2t-2,t-3}•{1,2,1}=0求t,怎么算的
问题描述:
{t-1,2t-2,t-3}•{1,2,1}=0求t,怎么算的
答
1x(t-1)+2X(2t-2)+1x(t-3)=0 t-1+4t-4+t-3=0 6t=8 t=4/3
{t-1,2t-2,t-3}•{1,2,1}=0求t,怎么算的
1x(t-1)+2X(2t-2)+1x(t-3)=0 t-1+4t-4+t-3=0 6t=8 t=4/3