[(y-2x)(-2x-y)-4(x-2y)²]÷3y,其中x=-3/16,y=-3/17

问题描述:

[(y-2x)(-2x-y)-4(x-2y)²]÷3y,其中x=-3/16,y=-3/17

[(y-2x)(-2x-y)-4(x-2y)²]÷3y,其中x=-3/16,y=-3/17=(4x²-y²-4x²+16xy-16y²)÷3y=(16xy-17y²)/3y=16x/3-17y/3=16/3×(-3/16)-17/3×(-3/17)=-1+1=0