x-2y+z=5 ① x-y=2 ② 2x+3y+z=1③

问题描述:

x-2y+z=5 ① x-y=2 ② 2x+3y+z=1③
三元一次方程求解,

x-2y+z=5 ① x-y=2 ② 2x+3y+z=1③
x=y+2;
2-y+z=5 ①
2y+4+3y+z=1③;
z-y+2= 5①;
z-y=3①
5y+z+3=0③;
z=y+3
③ - ①
6y+3=-3
y=-1
x=1
z=2