化简(2/3)(sin(2π/3-C)+sinC)
问题描述：
化简(2/3)(sin(2π/3-C)+sinC)
答
化简(2/3)[sin(2π/3-C)+sinC]
原式=(2/3)[sin(π-π/3-C)+sinC]=(2/3)[sin(π/3+C)+sinC]
=(4/3)sin(π/6+C)cos(π/6)=(2√3/3)sin(π/6+C)