已知弧长6390,弧高690,求半径和玄长以及圆心角
问题描述：
已知弧长6390,弧高690,求半径和玄长以及圆心角
答
已知弧长C=6390,弧高H=690,求半径R和玄长L以及圆心角A?Rn+1=(1-(Rn*COS(C/(2*Rn))-Rn+H)/((C/2)*SIN(C/(2*Rn))-H))*RnR0=7397R1=7275.337R2=7279.117R3=7279.121R4=7279.121R=7279.121A=C/R=6390/7279.121=0.877853...