【急】已知抛物线0.5X^2+mx+1的顶点在x轴上则m=
问题描述:
【急】已知抛物线0.5X^2+mx+1的顶点在x轴上则m=
答
y = 1/2 (x+m)^2 + 1 -m^2/2
顶点在x轴上,则 1 -m^2/2 =0
m^2 =2
m =√2 或-√2