大客车与小客车同时从A市出发到B市,客车每小时行驶90千米,小汽车第一小时行驶60千米,以后每小时增加5千米,小汽车需要（ ）小时追上客车?要算式和解释.

(30/5)*2+1=13小时 解释，第一小时大客车比小汽车快30千米，因小汽车每小时增加5千米，那么到（30/5）+1=7小时时，两车速度相等，那么要再经过30/5=6小时时小客车的速度比大客车快30千米，故小汽车需要（ 13 ）小时追上客车

设X小时追上，此时：
客车行驶距离为：90X千米；
小客车行驶距离：60+(60+5)+（60+5*2)+。。。+（60+5*（X－1)）＝60X+5*（1+（X－1)）/2 ＝60X+2.5X*（X-1)
二者距离相等，所以：90X＝60X+2.5X*（X-1)
整理得：2.5（X-1)=30
解得：X＝13
即，13小时后追上。

13个小时
用的最笨的方法

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(30/5)*2+1=13小时
解释,第一小时大客车比小汽车快30千米,因小汽车每小时增加5千米,那么到（30/5）+1=7小时时,两车速度相等,那么要再经过30/5=6小时时小客车的速度比大客车快30千米,故小汽车需要（ 13 ）小时追上客车