cos12°cos24°cos48°cos96°详细过程..
问题描述：
cos12°cos24°cos48°cos96°详细过程..
cos12°cos24°cos48°cos96°=?
答
应该是相乘,以下°全部省略原式＝sin12cos12cos24cos48cos96/sin12＝sin24cos24cos48cos96/(2sin12)＝sin48cos48cos96/(4sin12)＝sin96cos96/(8sin12)＝sin192/(16sin12)＝-sin12/(16sin12)＝-1/16...