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计算:[1/(x-y) - 1/(x+y) + 2y/(x^2 + y^2) - 4x^2 y/(x^4 + y^4)

分类: 作业答案 • 2022-05-23 21:04:23
问题描述：

计算:[1/(x-y) - 1/(x+y) + 2y/(x^2 + y^2) - 4x^2 y/(x^4 + y^4)

答

[1/(x-y) - 1/(x+y) + 2y/(x^2 + y^2) - 4x^2 y/(x^4 + y^4)=2y/(x^2-y^2)+2y/(x^2 + y^2) - 4x^2 y/(x^4 + y^4)=4x^2y/(x^4-y^4)- 4x^2 y/(x^4 + y^4)=8x^2y^5/(x^8-y^8)

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