x+y+z=3200 (2/3)x+(3/4)y+(4/5)z=2400 (4/5)x+(3/4)y+(2/3)z=2320这道3元一次方程怎么解?
问题描述:
x+y+z=3200 (2/3)x+(3/4)y+(4/5)z=2400 (4/5)x+(3/4)y+(2/3)z=2320这道3元一次方程怎么解?
答
x+y+z=3200 (2/3)x+(3/4)y+(4/5)z=2400 (4/5)x+(3/4)y+(2/3)z=2320这道3元一次方程怎么解?