已知【(x-1)(x-2)分之5x+1】=(x-1分之A)+(x-2分之11),求A的值
问题描述：
已知【(x-1)(x-2)分之5x+1】=(x-1分之A)+(x-2分之11),求A的值
答
两边同乘人(X-1)(X-2)得
5X+1=A(X-2)+11(X-1)化解得
A(X-2)=-6(X-2)得A=-6
答
∵(5x+1)/[(x-1)(x-2)]=A/(x-1)+11/(x-2)
两边同时乘以(x-1)(x-2):
5x+1=A(x-2)+11(x-1)
即5x+1=(A+11)x-2A-11
∴{5=A+11
{1=-2A-11
解得A=-6