一道分式计算题,计算；（a的平方/a+1）-a+1快
问题描述：
一道分式计算题,
计算；（a的平方/a+1）-a+1
快
答
答案：a²/(a+1)-a+1
=a²/(a+1)-(a-1)
=a²/(a+1)-(a-1)(a+1)/(a+1)
=a²/(a+1)-(a²-1)/(a+1)
=(a²-a²+1)/(a+1)
=1/(a+1)
答
a²/(a+1)-a+1=(a²-a²-a+a+1)/(a+1)=1/(a+1)。
答
a²/(a+1)-a+1
=a²/(a+1)-(a-1)
=a²/(a+1)-(a-1)(a+1)/(a+1)
=a²/(a+1)-(a²-1)/(a+1)
=(a²-a²+1)/(a+1)
=1/(a+1)