2a=3b2a=3b求4a²+12ab+9a²/2a²+5ab+3b²
问题描述:
2a=3b2a=3b求4a²+12ab+9a²/2a²+5ab+3b²
答
应该是:(4a²+12ab+9b²)/(2a²+5ab+3b²)
=(2a+3b)^2/(2a+3b)(a+b)
=(2a+3b)/(a+b)
代入:2a=3b
=(3b+3b)/(b+3b/2)
=6b/(5b/2)
=6/(5/2)
=6*2/5
=12/5