求解∫cos^2(1-2x)dx,∫(sin ax cos ax) 用第二积分换元法做得不对啊

1)syms x
>> int('(cos(1-2*x))^2',x)

ans =

x/2 + sin(4*x - 2)/8
2)
>> syms x a
>> int('sin(a*x)*cos(a*x)',x)

ans =

-cos(2*a*x)/(4*a)

∫cos^2(1-2x)dx= ∫ [cos(2-4x)+1]/2 dx = [ ∫cos(2-4x)dx ]/2+∫(1/2)dx= -[∫cosudu]/8 +x/2+C=(-sinu)/8 + x/2+C=[-sin(2-4x)]/8 +x/2+C∫(sin ax cos ax) dx=[ ∫(sin ax)d sinax ]/a=(sin^2 ax) /2a +C...