解二元一次方程组,(1){1/2x+1/3y=4/3,4x-y=3(2) {2x-3y=1,4分之y+1=3分之x+2(3) {0.1x-y=0.5,1.2x+0.5y=6
问题描述:
解二元一次方程组,
(1){1/2x+1/3y=4/3,4x-y=3
(2) {2x-3y=1,4分之y+1=3分之x+2
(3) {0.1x-y=0.5,1.2x+0.5y=6
答
(1)1/2x+1/3y=4/3 两边同乘3得
{3/2X+Y=4,4X-Y=3}
得(11/2)X=7
X=14/11,Y=-9/11