您的位置: 首页  >  作业答案  >  其他  >  函数y=根号2sin(x+π/4)+1的定义域为什么?A.[2kπ-5π/12,2kπ+11π/12]k∈zB.[kπ-5π/12,kπ+11π/12]k∈zC[2kπ-11π/12,2kπ+5π/12]k∈zD[kπ-11π/12,kπ+5π/12]k∈z

函数y=根号2sin(x+π/4)+1的定义域为什么?A.[2kπ-5π/12,2kπ+11π/12]k∈zB.[kπ-5π/12,kπ+11π/12]k∈zC[2kπ-11π/12,2kπ+5π/12]k∈zD[kπ-11π/12,kπ+5π/12]k∈z

分类: 作业答案 • 2021-12-19 11:37:54
问题描述：

函数y=根号2sin(x+π/4)+1的定义域为什么?
A.[2kπ-5π/12,2kπ+11π/12]k∈z
B.[kπ-5π/12,kπ+11π/12]k∈z
C[2kπ-11π/12,2kπ+5π/12]k∈z
D[kπ-11π/12,kπ+5π/12]k∈z

答

2sin(x+π/4)+1>=0
sin(x+π/4)>=-1/2
-π/3+2kπ

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