sin(2x-π/4)=根号3/2 ,求x
问题描述:
sin(2x-π/4)=根号3/2 ,求x
答
sin(2x-π/4)=√3/2
2x-π/4=π/3+2kπ或2x-π/4=2π/3+2kπ
2x=π/4+π/3+2kπ或2x=π/4+2π/3+2kπ
2x=7π/12+2kπ或2x=11π/12+2kπ
x=7π/24+kπ或2x=11π/24+kπ (k∈Z)