解不等式：（1/5）^[ (log2 X)^2-1]
问题描述：
解不等式：（1/5）^[ (log2 X)^2-1]
数学人气：761 ℃时间：2019-08-19 18:23:35
优质解答
（1/5）^[ (log2 X)^2-1] (log2 X)^2-1 > 2x(2+log底数为根号2 X),令log2 X = y=>y^2 -1 > 4 + 2( log2X/log2根号2)=> y^2 > 5 + 4y => y> 5 => x > 32
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答
（1/5）^[ (log2 X)^2-1] (log2 X)^2-1 > 2x(2+log底数为根号2 X),令log2 X = y=>y^2 -1 > 4 + 2( log2X/log2根号2)=> y^2 > 5 + 4y => y> 5 => x > 32