f(x)=2sin(2x+π/6)
问题描述:
f(x)=2sin(2x+π/6)
如上,x∈[π/12,π/2],函数的值域是?
答
π/12π/6π/3sin在(π/3,π/2)是增函数
(π/2,7π/6)是减函数
所以π/2时最大,7π/6时最小
sinπ/6=1,sin7π/6=-1/2
所以值域[-1,2]