求下列三角函数的值(1)cos(-1050°)(2)tan19/3π
问题描述:
求下列三角函数的值(1)cos(-1050°)(2)tan19/3π
答
(1)cos(-1050°)
=cos(-1050°+3*360°)
=cos(-1050°+1080°)
=cos30°
=√3/2
(2)tan19/3π
=tan(6π+π/3)
=tanπ/3
=√3