求下列三角函数的值(1)cos(-1050°)(2)tan19/3π

问题描述:

求下列三角函数的值(1)cos(-1050°)(2)tan19/3π

(1)cos(-1050°)
=cos(-1050°+3*360°)
=cos(-1050°+1080°)
=cos30°
=√3/2
(2)tan19/3π
=tan(6π+π/3)
=tanπ/3
=√3