(1-(a+1分之2））的平方除以（a+1)分之(a-1)
问题描述：
(1-(a+1分之2））的平方除以（a+1)分之(a-1)
答
上面的式子通分，然后化简就好，不明白再联系
答
[1-2/(a+1)]^2/[(a-1)/(a+1)]
=[(a-1)/(a+1)]^2/[(a-1)/(a+1)]
=[(a-1)/(a+1)]^2*(a+1)/(a-1)
=(a-1)/(a+1)
答
原式=[(a+1-2)/(a+1)]²×[(a+1)/(a-1)]
=[(a-1)/(a+1)]²×[(a+1)/(a-1)]
=[(a-1)²/(a+1)²]×[(a+1)/(a-1)]
=(a-1)/(a+1)
答
[1-2/(a+1)]^2/[(a-1)/(a+1)]
=[(a+1-2)/(a+1)]^2/[(a-1)/(a+1)]
=(a-1)^2/(a+1)^2*(a+1)/(a-1)
=(a-1)/(a+1)