已知z=cos(-π/6)+isin(-π/6),则argz^3
问题描述：
已知z=cos(-π/6)+isin(-π/6),则argz^3
答
z=cos(-π/6)+isin(-π/6)
z^3=cos(-π/2)+isin(-π/2)
=cos(3π/2)+isin(3π/2)
所以 argz^3=3π/2