(-1 2 0) (2 a b) (0 c -1)是正交矩阵 求a b c
问题描述:
(-1 2 0) (2 a b) (0 c -1)是正交矩阵 求a b c
答
-1 2 02 a b0 c -1正交矩阵列向量两两正交(-1 2 0) (2 a b)正交得-2+2a = 0a=1.(-1 2 0) (0 c -1)正交得2c=0c=0(2 a b) (0 c -1)正交得(2 1 b) (0 0 -1)正交所以 -b=0所以b=0.注:题目有问题.正交矩...