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sin(30°+α)×tan(135°+α)×tan(135°-α)1/cos(60°-α)

分类: 作业答案 • 2022-05-09 20:50:17
问题描述：

sin(30°+α)×tan(135°+α)×tan(135°-α)1/cos(60°-α)

答

sin(30°+α)×tan(135°+α)×tan(135°-α)1/cos(60°-α)=sin(30°+α)×tan(90°+45°+α)×tan(180°-(45°+α))1/cos(90°-(30°+α))=sin(30°+α)×[-cot(45°+α)]×[-tan((45°+α))]1/sin(30°+α)=1

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