若a^2+a-1=0,则a^4+2a^3-3a^2-4a+3=?
问题描述:
若a^2+a-1=0,则a^4+2a^3-3a^2-4a+3=?
答
a^4+2a^3-3a^2-4a+3
=a^2(a^2+a-1)+a^3-2a^2-4a+3
=a^3-2a^2-4a+3
=a(a^2+a-1)-3a^2-3a+3
=-3(a^2+a-1)
=0