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3+i/(4—2i)—7—2i/1+i

分类: 作业答案 • 2022-05-09 11:57:10

问题描述：

3+i/(4—2i)—7—2i/1+i

答

(3＋i)/(4－2i)=[(3＋i)(4＋2i)]/[(4－2i)(4＋2i)]=[10＋10i]/20=(1/2)＋(1/2)i
(7－2i)/(1＋i)=[(7－2i)(1－i)]/[(1＋i)(1－i)]=[5－9i]/2=(5/2)－(9/2)i
则原式=－2＋5i

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计算:(3+i/4-2i)-(7-2i/1+i)=
4－2i分之3+i减1+i分之7－2i