3−sin70°2−cos210°=_.

问题描述:

3−sin70°
2−cos210°
=______.

3−sin70°
2−cos210°
=
3−sin70°
2−
1+cos20°
2
=
2(3−sin70°)
3−cos 20°
=
2(3−cos20°)
3−cos 20°
=2
故答案为:2