一个整式加上ab-2ac,得3ac-ab,求这个整式减去ab-2ac的值

问题描述:

一个整式加上ab-2ac,得3ac-ab,求这个整式减去ab-2ac的值
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原整式为(3ac-ab)-(ab-2ac)=3ac-ab-ab+2ac=5ac-2ab5ac-2ab-(ab-2ac)=5ac-2ab-ab+2ac=7ac-3ab