2(x-1)²+▏x+2y+1▕=0,求½x²ºº³y²º¹º+y的值?
问题描述:
2(x-1)²+▏x+2y+1▕=0,求½x²ºº³y²º¹º+y的值?
答
绝对值和完全平方非负
x-1=0
x=1
x+2y+1=0
1+2y+1=0
y=-1
½x²ºº³y²º¹º+y
=1/2×1×(-1)^2010-1
=1/2-1
=-1/2▏a-c-2▕+﹙3a-6b-7﹚2+▏3b+3c-4▕=0,求﹙﹣3ab﹚×﹙﹣a2c﹚×6ab2的值