若直线mx+2ny-4=0(m,n∈R)将圆x2+y2-4x-2y-4=0分成两段相等的弧,则m+n等于( ) A.-2 B.-1 C.1 D.2
问题描述:
若直线mx+2ny-4=0(m,n∈R)将圆x2+y2-4x-2y-4=0分成两段相等的弧,则m+n等于( )
A. -2
B. -1
C. 1
D. 2
答
由直线将圆分成等弧可得直线过圆心,将圆心坐标(2,1)代入直线mx+2ny-4=0,
可得2m+2n=4,求得:m+n=2,
故选:D.