若0
问题描述：
若0
数学人气：759 ℃时间：2020-07-04 01:51:29
优质解答
00
又tan x=3tan y
则tan（x-y）=(tanx-tany)/(1+tanx*tany)
=2tany/(1+3tany*tany)
=2/(1/tany+3tany)
又1/tany+3tany≥2/根号3
则tan（x-y）≤根号3/3
则x-y≤π/6
即x-y≤30º
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答
00
又tan x=3tan y
则tan（x-y）=(tanx-tany)/(1+tanx*tany)
=2tany/(1+3tany*tany)
=2/(1/tany+3tany)
又1/tany+3tany≥2/根号3
则tan（x-y）≤根号3/3
则x-y≤π/6
即x-y≤30º