(x-1)的平方+2x(x-1)=0
问题描述:
(x-1)的平方+2x(x-1)=0
答
(x-1)的平方加2x(x-1)=0
(x-1)²+2x(x-1)=0
(x-1)[(x-1)+2x]=0
(x-1)(3x-1)=0
x-1=0,x1=1;
3x-1=0,x2=1/3;