x,y满足方程组{3ax+4y=9,6ax+5y=27 ,那么 aax+y的值是?
问题描述:
x,y满足方程组{3ax+4y=9,6ax+5y=27 ,那么 aax+y的值是?
答
3ax+4y=9,⑴
6ax+5y=27 ⑵
⑵- ⑴得
3ax+y=18