根号下(x1-x2)平方+(Y1-Y2)平方=Z 求Y2=?

问题描述:

根号下(x1-x2)平方+(Y1-Y2)平方=Z 求Y2=?

平方(x1-x2)²+(y1-y2)²=z²(y1-y2)²=z²-(x1-x2)²y1-y2=±√[z²-(x1-x2)²]y2=y1+√[z²-(x1-x2)²],y2=y1-√[z²-(x1-x2)²]