因式分解x4+y4+z4-2x2y2-2x2z2-2y2z2
问题描述：
因式分解x4+y4+z4-2x2y2-2x2z2-2y2z2
x,y,后的2为平方.
答
x^4+y^4+z^4-2x^2y^2-2x^2z^2-2y^2z^2=x^4-2x^2y^2+y^4+z^4-2x^2z^2-2y^2z^2=(x^4-2x^2y^2+y^4)+(z^4-2x^2z^2-2y^2z^2)=(x^2-y^2)^2+z^4-2y^2z^2+2z^2x^2-4z^2x^2=(x^2-y^2)^2+2z^2(x^2-y^2)+z^4-4z^2x^2=(x^2-y^2+z...