log2[log2/1(log2x)]=0 求 x

问题描述:

log2[log2/1(log2x)]=0 求 x

log2[log2/1(log2x)]=0=log2(1)
所以log2/1(log2x)=1=log2/1(2/1)
log2x=2/1
x=2^(2/1)
x=√2